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Description of Statistical Computation

Author's title

Author*The author of this computation has been verified*
R Software Modulerwasp_STARS_Bullying_Study_alt.wasp
Title produced by softwareChi-Square Test
Date of computationTue, 16 Nov 2010 15:08:49 +0000
Cite this page as followsStatistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?v=date/2010/Nov/16/t12899200238d0mt0wztfgkiyk.htm/, Retrieved Sun, 05 May 2024 00:18:00 +0000
Statistical Computations at FreeStatistics.org, Office for Research Development and Education, URL https://freestatistics.org/blog/index.php?pk=95893, Retrieved Sun, 05 May 2024 00:18:00 +0000
QR Codes:

Original text written by user:
IsPrivate?No (this computation is public)
User-defined keywords
Estimated Impact104

Tree of Dependent Computations

Family? (F = Feedback message, R = changed R code, M = changed R Module, P = changed Parameters, D = changed Data)
-     [Chi-Square Test] [] [2010-11-16 14:55:02] [7f2363d2c77d3bf71367965cc53be730]
F   P   [Chi-Square Test] [] [2010-11-16 15:01:10] [7f2363d2c77d3bf71367965cc53be730]
F    D      [Chi-Square Test] [] [2010-11-16 15:08:49] [4dba6678eac10ee5c3460d144a14bd5c] [Current]
Feedback Forum
2010-11-19 13:56:10 [7d66e2e510b144c68ca0882fd178e17c] [reply] 
Je hebt niet de juiste calculator gebruikt. De calculator die jij hebt gebruikt toont geen grafische weergave van de verwachte en werkelijke waarden. Dit is niet totaal fout, maar je kan zo geen volledige analyse maken. Je moet de calculator Chi-Squared and McNemar Tests gebruiken.

Een voorbeeld voor deze vergelijking: http://www.freestatistics.org/blog/index.php?v=date/2010/Nov/19/t1290168409nf75hyquhpxnzfx.htm/

Je analyse is voor de helft gemaakt.Omdat er dus een samenhang is gaan we kijken of dit een negatief of positief verband. We zien dat de 4 balken niet gekleurd zijn, dit wijst op geen significante verschillen onderling en dat er dus geen verband is. Als we het totale beeld bekijken, is er wel een significant verschil. Vervolgens zien we dat er een positief verband is tussen happiness en separated. Hoe zie je dit? De twee diagonalen spreken elkaar tegen en daarom kijken we naar de hoofddiagonaal. Bij de balk van Hi happiness en Hi separated, ligt de werkelijke waarde boven de verwachte waarde en dus is er een positief verband.
2010-11-20 08:56:14 [7d66e2e510b144c68ca0882fd178e17c] [reply] 
Je kon ook hier gebruik maken van de verfijnde indeling (a,b,c,d) ipv de groffe indeling (Hi, Lo). Ik had het gedaan volgens de groffe indeling.

Post a new message

Dataset

Dataseries X:
Download CSV
Histogram
Boxplots 
'HI'	'HI'
'HI'	'LO'
'LO'	'HI'
'LO'	'LO'
'HI'	'HI'
'HI'	'LO'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'HI'	'HI'
'LO'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'HI'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'HI'
'HI'	'LO'
'LO'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'HI'	'LO'
'LO'	'LO'
'HI'	'LO'
'HI'	'HI'
'HI'	'LO'
'HI'	'LO'
'LO'	'LO'
'HI'	'LO'
'HI'	'LO'
'LO'	'LO'
'HI'	'LO'
'HI'	'LO'
'HI'	'LO'
'LO'	'LO'
'LO'	'LO'
'LO'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'LO'	'LO'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'LO'	'HI'
'LO'	'LO'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'LO'	'HI'
'LO'	'HI'
'LO'	'LO'
'LO'	'HI'
'LO'	'HI'
'HI'	'HI'
'HI'	'LO'
'LO'	'HI'
'LO'	'HI'
'LO'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'LO'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'LO'
'HI'	'LO'
'LO'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'LO'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'LO'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'LO'	'HI'
'HI'	'HI'
'LO'	'LO'
'HI'	'HI'
'LO'	'LO'
'HI'	'HI'
'HI'	'HI'
'LO'	'HI'
'LO'	'HI'
'HI'	'HI'
'LO'	'LO'
'LO'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'LO'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'HI'	'LO'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'LO'	'LO'
'HI'	'HI'
'HI'	'LO'
'HI'	'HI'
'HI'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'HI'
'HI'	'HI'
'LO'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'HI'
'HI'	'LO'
'HI'	'LO'
'HI'	'LO'
'LO'	'HI'
'LO'	'LO'
'LO'	'LO'
'HI'	'HI'
'LO'	'HI'
'HI'	'HI'
'LO'	'HI'
'LO'	'HI'
'LO'	'LO'
'LO'	'LO'
'HI'	'HI'
'HI'	'HI'
'LO'	'LO'
'LO'	'HI'
'LO'	'HI'

Tables (Output of Computation)





Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'George Udny Yule' @ 72.249.76.132

\begin{tabular}{lllllllll}
\hline
Summary of computational transaction \tabularnewline
Raw Input & view raw input (R code)  \tabularnewline
Raw Output & view raw output of R engine  \tabularnewline
Computing time & 1 seconds \tabularnewline
R Server & 'George Udny Yule' @ 72.249.76.132 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=95893&T=0

[TABLE]
[ROW][C]Summary of computational transaction[/C][/ROW]
[ROW][C]Raw Input[/C][C]view raw input (R code) [/C][/ROW]
[ROW][C]Raw Output[/C][C]view raw output of R engine [/C][/ROW]
[ROW][C]Computing time[/C][C]1 seconds[/C][/ROW]
[ROW][C]R Server[/C][C]'George Udny Yule' @ 72.249.76.132[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=95893&T=0

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=95893&T=0

As an alternative you can also use a QR Code:  
QR Code


The GUIDs for individual cells are displayed in the table below:

Summary of computational transaction
Raw Inputview raw input (R code)
Raw Outputview raw output of R engine
Computing time1 seconds
R Server'George Udny Yule' @ 72.249.76.132






Tabulation of Results
Hapiness x Separate
HILO
HI6538
LO2534

\begin{tabular}{lllllllll}
\hline
Tabulation of Results \tabularnewline
Hapiness  x  Separate \tabularnewline
  & HI & LO \tabularnewline
HI & 65 & 38 \tabularnewline
LO & 25 & 34 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=95893&T=1

[TABLE]
[ROW][C]Tabulation of Results[/C][/ROW]
[ROW][C]Hapiness  x  Separate[/C][/ROW]
[ROW][C] [/C][C]HI[/C][C]LO[/C][/ROW]
[C]HI[/C][C]65[/C][C]38[/C][/ROW]
[C]LO[/C][C]25[/C][C]34[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=95893&T=1

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=95893&T=1

As an alternative you can also use a QR Code:  
QR Code


The GUIDs for individual cells are displayed in the table below:

Tabulation of Results
Hapiness x Separate
HILO
HI6538
LO2534






Tabulation of Expected Results
Hapiness x Separate
HILO
HI57.2245.78
LO32.7826.22

\begin{tabular}{lllllllll}
\hline
Tabulation of Expected Results \tabularnewline
Hapiness  x  Separate \tabularnewline
  & HI & LO \tabularnewline
HI & 57.22 & 45.78 \tabularnewline
LO & 32.78 & 26.22 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=95893&T=2

[TABLE]
[ROW][C]Tabulation of Expected Results[/C][/ROW]
[ROW][C]Hapiness  x  Separate[/C][/ROW]
[ROW][C] [/C][C]HI[/C][C]LO[/C][/ROW]
[C]HI[/C][C]57.22[/C][C]45.78[/C][/ROW]
[C]LO[/C][C]32.78[/C][C]26.22[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=95893&T=2

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=95893&T=2

As an alternative you can also use a QR Code:  
QR Code


The GUIDs for individual cells are displayed in the table below:

Tabulation of Expected Results
Hapiness x Separate
HILO
HI57.2245.78
LO32.7826.22






Statistical Results
Pearson's Chi-squared test with Yates' continuity correction
Chi Square Statistic5.72
Degrees of Freedom1
P value0.02

\begin{tabular}{lllllllll}
\hline
Statistical Results \tabularnewline
Pearson's Chi-squared test with Yates' continuity correction \tabularnewline
Chi Square Statistic & 5.72 \tabularnewline
Degrees of Freedom & 1 \tabularnewline
P value & 0.02 \tabularnewline
\hline
\end{tabular}
%Source: https://freestatistics.org/blog/index.php?pk=95893&T=3

[TABLE]
[ROW][C]Statistical Results[/C][/ROW]
[ROW][C]Pearson's Chi-squared test with Yates' continuity correction[/C][/ROW]
[ROW][C]Chi Square Statistic[/C][C]5.72[/C][/ROW]
[ROW][C]Degrees of Freedom[/C][C]1[/C][/ROW]
[ROW][C]P value[/C][C]0.02[/C][/ROW]
[/TABLE]
Source: https://freestatistics.org/blog/index.php?pk=95893&T=3

Globally Unique Identifier (entire table): ba.freestatistics.org/blog/index.php?pk=95893&T=3

As an alternative you can also use a QR Code:  
QR Code


The GUIDs for individual cells are displayed in the table below:

Statistical Results
Pearson's Chi-squared test with Yates' continuity correction
Chi Square Statistic5.72
Degrees of Freedom1
P value0.02


Figures (Output of Computation)

Input Parameters & R Code

Parameters (Session):
par1 = 1 ; par2 = 2 ; par3 = Pearson Chi-Square ;
Parameters (R input):
par1 = 1 ; par2 = 2 ; par3 = Pearson Chi-Square ;
R code (references can be found in the software module):
cat1 <- as.numeric(par1) #
cat2<- as.numeric(par2) #
simulate.p.value=FALSE
if (par3 == 'Exact Pearson Chi Square by simulation') simulate.p.value=TRUE
x <- t(x)
(z <- array(unlist(x),dim=c(length(x[,1]),length(x[1,]))))
(table1 <- table(z[,cat1],z[,cat2]))
(V1<-dimnames(y)[[1]][cat1])
(V2<-dimnames(y)[[1]][cat2])
load(file='createtable')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Tabulation of Results',ncol(table1)+1,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,paste(V1,' x ', V2),ncol(table1)+1,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a, ' ', 1,TRUE)
for(nc in 1:ncol(table1)){
a<-table.element(a, colnames(table1)[nc], 1, TRUE)
}
a<-table.row.end(a)
for(nr in 1:nrow(table1) ){
a<-table.element(a, rownames(table1)[nr], 1, TRUE)
for(nc in 1:ncol(table1) ){
a<-table.element(a, table1[nr, nc], 1, FALSE)
}
a<-table.row.end(a)
}
a<-table.end(a)
table.save(a,file='mytable.tab')
(cst<-chisq.test(table1, simulate.p.value=simulate.p.value) )
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Tabulation of Expected Results',ncol(table1)+1,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a,paste(V1,' x ', V2),ncol(table1)+1,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a, ' ', 1,TRUE)
for(nc in 1:ncol(table1)){
a<-table.element(a, colnames(table1)[nc], 1, TRUE)
}
a<-table.row.end(a)
for(nr in 1:nrow(table1) ){
a<-table.element(a, rownames(table1)[nr], 1, TRUE)
for(nc in 1:ncol(table1) ){
a<-table.element(a, round(cst$expected[nr, nc], digits=2), 1, FALSE)
}
a<-table.row.end(a)
}
a<-table.end(a)
table.save(a,file='mytable1.tab')
a<-table.start()
a<-table.row.start(a)
a<-table.element(a,'Statistical Results',2,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a, cst$method, 2,TRUE)
a<-table.row.end(a)
a<-table.row.start(a)
a<-table.element(a, 'Chi Square Statistic', 1, TRUE)
a<-table.element(a, round(cst$statistic, digits=2), 1,FALSE)
a<-table.row.end(a)
if(!simulate.p.value){
a<-table.row.start(a)
a<-table.element(a, 'Degrees of Freedom', 1, TRUE)
a<-table.element(a, cst$parameter, 1,FALSE)
a<-table.row.end(a)
}
a<-table.row.start(a)
a<-table.element(a, 'P value', 1, TRUE)
a<-table.element(a, round(cst$p.value, digits=2), 1,FALSE)
a<-table.row.end(a)
a<-table.end(a)
table.save(a,file='mytable2.tab')